Question

5) A body having a mass of 4 gram execute SHM the force acting on the body, when
the displacement is 0.08m us 0.239 N. Find the time period. If the maximum
velocity is 0.5ms', find the amplitude and maximum acceleration.​

Answer 1

Answer:

Given:

mass = 4g = 4/1000 kg

disp. = 0.08 m

F = 0.239 N

Umax. = 0.5 m/s

Explanation:

Umax ( velocity) = ωα

0.5 = ω × 0.08

ω = 6.25 /s

Time period = 2π/ω

                     = 2 × 3.14/6.25

                     = 1.0048 s

Max. acceleration = ω^2y

                              = ( 6.25)^2 × .08

                              = 3.125m/s^2

amplitute is max. displacement .Here disp. given is 0.08 m

A = 0.08m

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