Question

5. A body is projected vertically upward with speed 10 m/s and other at same time with same speed in downwards direction from the top of a tower. The magnitude of acceleration of first body w.r.t. second is {take g = 10 m/s^2} (1) Zero (2) 10 m/s^2 (3) 5 m/s^2 (4) 20 m/s^2

Answer 1

body 1                                           body 2
U=10 m/s                                  U = 0       ( in case o free falling object)
V=0                                            A= 10m/s sq (ACCELERATION DUE TO GRAVITY)
A= V-U/t                                   (here acceleration is negative)
=0 - 10 /1sec
A= -10 m/sec sq
 
but in question it asked abt magnitude so for both the body magnitude wud be 10 m /s sq.
so A1 w.r.t A2
is
A1-A2 (10 - 10 = 0)
= 0 (ans)

Answer 2

 a body is projected vertically upwards with speed 10 m/s other at same time with speed in downward direction the magnitude of acceleration of first bo. ... body 1 body 2. U=10 m/s U = 0 ( in case o free falling object) V=0 A= 10m/s sq (ACCELERATION DUE TO GRAVITY) A= V-U/t