Question

5. A body of mass 4 kg is dropped from a height of 1 m. Its KE as it touches the ground is
(g = 10 m/s2);
(a) 40 N
(b) 40 J
(c) 40 kg f
(d) 40 N/m2​

Answer 1

Answer:

d

Explanation:

1. v^2= root of 2gh = root of 2× 10 ×1= root 20 = 2 root 5
2. v = 2 root 5
3. substitute in formula KE = 1/2 mv^2
4. KE= 1/2× 4 × 2 root 5 ^2
5. KE= 2 ×4×5= 40N/m^2

Answer 2

Answer is option d .............