5) A body of mass 5 kg initially at rest is subjected to a force of 29N.What is the kinetic energy
acquired by the body at the end of 10 s.
Answers
Given :
Mass of the body = 5 kg
Applied force = 29N
Initial velocity = zero
To Find :
Kinetic energy of body after 10 s.
Solution :
❖ First of all we need to find acceleration of the body.
- As per newton's second law of motion force is measured as the product of mass and acceleration.
Mathematically, F = m a
By substituting the given values;
➙ F = m a
➙ 29 = 5 × a
➙ a = 29/5
➙ a = 5.8 m/s²
♦ Final velocity of body can be calculated by using first equation of kinematics
- v = u + at
» v denotes final velocity
» u denotes initial velocity
» a denotes acceleration
» t denotes time
➠ v = u + at
➠ v = 0 + (5.8)(10)
➠ v = 58 m/s²
♦ Kinetic energy of the body :
➛ k = 1/2 mv²
➛ k = 1/2 × 5 × (58)²
➛ k = 16820/2
➛ k = 8410 J = 8.41 kJ
Answer:-
The kinetic energy acquired by the body at the end of 10s is 8.41 kJ
Explanation:-
Given:-
- Mass of body ( m ) = 5 kg
- Initial velocity ( u ) = 0
- Force applied ( F ) = 29 N
- Time ( t ) = 10s
To find:-
What is the kinetic energy acquired by the body at the end of 10 s ?
Solution:-
We know that,
⠀⠀
Now,
Velocity of body at the end of 10s ,
⠀⠀⠀⠀⠀⠀⠀⠀
Now,
Kinetic energy acquired by the body ,
⠀⠀⠀⠀⠀⠀⠀
The kinetic energy acquired by the body at the end of 10s is 8.41 kJ