Question

5) A body of mass 5kg is acted upon by two
perpendicular forces of 8N & 6N. Give the
magnitude of the force.​

Answer 1

body of mass m is 5 kg

R=(8) 2 +(−16 2 )= 64+36

=10N

θis angle made by force of 8 N

θ=tan −1 (−6/8)=−36.87 0

the negative sign indicates theta clockwise direction respect to the force of magnitude 8N

force is m X aa=f/m=10/5=2ms −2