5) A body of mass 5kg is acted upon by two
perpendicular forces of 8N & 6N. Give the
magnitude of the force.
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body of mass m is 5 kg
R=(8) 2 +(−16 2 )= 64+36
=10N
θis angle made by force of 8 N
θ=tan −1 (−6/8)=−36.87 0
the negative sign indicates theta clockwise direction respect to the force of magnitude 8N
force is m X aa=f/m=10/5=2ms −2
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