Math, asked by sahidmansoori1110162, 3 months ago

(5) A borrowed Rs 5000 from B and after 4
years B receives Rs 1,000 more than the
original amount given to A. What was the
rate of interest ?​

Answers

Answered by PAVITHRAA23
4

Answer:

Principal = Rs.5000

I = Rs.1000.

N = 4 years

To find R:

R=100IPN=100×10005000×4

=10020 = 5%

Answered by MissCardiologist
2

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Calculation of rate of interest

Answer: Rate of interest on which the money is borrowed by A from B is 5%.

Explanation:

Given that A borrowed Rs 5000 from B on Simple Interest.

After three years B received Rs 1000 more that the amount to A on Loan.

As amount given to A on loan = Rs 5000 , so amount received by B after four years = Rs 5000 + Rs 1000 = Rs 6000

This means Interest earned by B in four years = RS 6000 - Rs 5000 = Rs 1000

so S. I = Rs 1000  , Principal = Rs 5000 , time = 4 years

lets say rate of interest per year = y %

Formula for Simple interest tha is S.I is as follows

S.I = (Principal x Rate of interest x time) / 100

On substituting the values we get

1000 = ( 5000 x y x 4 ) / 100

solving the above expression for y we get

(1000 x 100)/(5000 x 4) = y

=> y = 5%

Hence rate of interest on which the money is borrowed by A from B is 5%..

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