Question

5. A box contains 2 red, 2 white and 2 blue balls. One ball is taken out of the box

at random. What is the probability that the ball drawn is not red and white​

Answer 1

Answer:

Total no. of balls-6 balls

No. of favourable outcome - 2 red - 2 white - 4 balls

P(E) - the ball drawn is not red and white.

P(E) = No. of favourable outcomes / Total no. of outcomes

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Answer 2

Answer:

Given data:

Red balls = 2

White balls = 2

Blue balls = 2

Total number of balls = 2+2+2 = 6

Here, we have to find probability that the ball drawn is not red and white.

This means we should find the probability that the ball drawn is to be blue.

P = One ball out of 2 blue balls ÷ Total number of balls

P = 2C1 ÷ 6C1

P = 2 ÷ 6

P = 0.33

P = 1/3.

So the probability that the ball drawn is not red and white is one third (1/3).