Physics, asked by omvvishwakarma1993, 2 months ago

5. A boy is travelling in a bus moving with a
velocity of 45 kmh-1. How much distance will the
boy travel in (a) 1 min, and (b) 1 s.​

Answers

Answered by tonystarky247
4

Answer:

velocity = 45 km/h = 45000 / (60×60) m/sec

= 12.5 m/sec

Distance = velocity × time

(a). for time = 1 min,

Distance = 12.5 × 1 × 60 = 750 meter

(b). for time = 1 sec,

Distance = 12.5 × 1 = 12.5 meter

Answered by saritathapaxettri18
2

Explanation:

here

initial velocity(u)= o m/s

final velovity(v)=45km/hr=

= 45km/1 hrs

= 45× 1000m/60sec

=12.5mls

time travel=1min=60 sec

we know that

acceleration(a)=v-u/t

12.5-0/60

=2.08

now

s=ut+1/2atsquare

0×60+1/2×2.08×60×60

S=3744m

so the distance is 3744m in 1 min

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