5. A boy is travelling in a bus moving with a
velocity of 45 kmh-1. How much distance will the
boy travel in (a) 1 min, and (b) 1 s.
Answers
Answered by
4
Answer:
velocity = 45 km/h = 45000 / (60×60) m/sec
= 12.5 m/sec
Distance = velocity × time
(a). for time = 1 min,
Distance = 12.5 × 1 × 60 = 750 meter
(b). for time = 1 sec,
Distance = 12.5 × 1 = 12.5 meter
Answered by
2
Explanation:
here
initial velocity(u)= o m/s
final velovity(v)=45km/hr=
= 45km/1 hrs
= 45× 1000m/60sec
=12.5mls
time travel=1min=60 sec
we know that
acceleration(a)=v-u/t
12.5-0/60
=2.08
now
s=ut+1/2atsquare
0×60+1/2×2.08×60×60
S=3744m
so the distance is 3744m in 1 min
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