Question

5.
A bus is beginning to move with an acceleration of
1m/s2. A boy who is 48m behind the bus starts
running at 10m/s. After what time will the boy be
able to catch the bus?
​

Answer 1

Answer:

Let D be the distance at which the boy catches the bus Time of running = t . This => 10t = D

Let D be the distance at which the boy catches the bus Time of running = t . This => 10t = DIn this time, bus moves a distance of ( 10t - 48) m

Let D be the distance at which the boy catches the bus Time of running = t . This => 10t = DIn this time, bus moves a distance of ( 10t - 48) m( 10t - 48) = (1/2) t ^2

Let D be the distance at which the boy catches the bus Time of running = t . This => 10t = DIn this time, bus moves a distance of ( 10t - 48) m( 10t - 48) = (1/2) t ^220t -96 -t^2 = 0

Let D be the distance at which the boy catches the bus Time of running = t . This => 10t = DIn this time, bus moves a distance of ( 10t - 48) m( 10t - 48) = (1/2) t ^220t -96 -t^2 = 0t = 12 & 8 s

Let D be the distance at which the boy catches the bus Time of running = t . This => 10t = DIn this time, bus moves a distance of ( 10t - 48) m( 10t - 48) = (1/2) t ^220t -96 -t^2 = 0t = 12 & 8 sAfter 8 second he meets the bus. And if he does not catch it , again he catches the bus in another 4 s.

Answer 2

correct anwer for the question above

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