Question

5. A can do a piece of work in 12 days and B alone can do it in 16 days. They worked together on it
for 3 days and then A left. How long did B take to finish the remaining work?
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Answer 1

Answer:

3 days

Step-by-step explanation:

Work done by A and B in 5 days

= 5\left ( \frac{1}{12}+\frac{1}{15} \right ) = 5\left ( \frac{5+4}{60} \right )

= 5\times \frac{9}{60} = \frac{9}{12} = \frac{3}{4}

Remaining work = 1-\frac{3}{4} = \frac{1}{4}

∴ Time taken by A = \frac{1}{4}\times 12 = 3\ days