5. A can do a piece of work in 40 days. He works at it for 8 days and then B finishes the
remaining work in 16 days. How long will they take to complete the work if they do it
together?
Answers
Answer:
40/3 or 13(1/3)
Step-by-step explanation:
work done by A in 1 day = 1/40
work done by A in 8 days = 1/40*5
= 1/5
The remaining part = 1-1/5
= 4/5
No. of days taken by Y to finish 4/5 part = 16 days
part of work done by Y in 1 day = (4/5)/16
= (4/5)(1/16)
= 1/20
If they work together = 1/40+1/20
= 3/40
So,
the no. days taken by both to complete the work =1/(3/40)
=40/3
or
13(1/3)
Answer:
Answer:
40/3 or 13(1/3)
Step-by-step explanation:
work done by A in 1 day = 1/40
work done by A in 8 days = 1/40*5
= 1/5
The remaining part = 1-1/5
= 4/5
No. of days taken by Y to finish 4/5 part = 16 days
part of work done by Y in 1 day = (4/5)/16
= (4/5)(1/16)
= 1/20
If they work together = 1/40+1/20
= 3/40
So,
the no. days taken by both to complete the work =1/(3/40)
=40/3
or
13(1/3)