Math, asked by tinnigupta103, 3 months ago


5. A can work twice as fast as B. If they together complete a work in 12 days, then in how many days will B alone
complete this work?

Answers

Answered by Anonymous
0

Answer:

36 days

Step-by-step explanation:

A works twice as fast as B. A and B finish a job in 12 days, working together.

Let A take x days to do the work, alone. So he does (1/x)th of the work in a day.

Then B take 2x days to do the work, alone. So he does (1/2x)th of the work in a day.

A do B together do (1/x)+(1/2x) = (1/12), or

3/2x = 1/12, r

2x = 36, or

x = 18

So A does the work in 18 days while B does the same work in 36 days, each working alone.

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Answered by ReetMohan
1

Answer:

B will complete the work in 36 days.

Step-by-step explanation:

A works twice as fast as B.

A and B finish a job by working together in 12 days.

Let A take x days to do the work ( alone ). So it does (1 /x)th of the work in a day.

Then B take 2x days to do the work ( alone ). So it does (1 /2x)th of the work in a day.

A and B together do (1 /x) + (1 /2x) = (1 /12), or

3/2x = 1/12, r

2x = 36, or

x = 18

Ans: B will do the same work as A in 36 days.

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