Physics, asked by slman295, 9 months ago

5. A cannon shell is fired straight up from the ground at an initial speed of 225 m/s. After how much time is the shell at a height of 6.20 × 102 m above the ground and mov- ing downward? (a) 2.96 s (b) 17.3 s (c) 25.4 s (d) 33.6 s (e) 43.0 s​

Answers

Answered by js45756825373
6

Explanation:

█ Explanation █

✦ Use the equation y(t) = y₀ + v₀t + ½at² to find the time.

✦ Plug in the values of the equation.

✦ 620 = 225t - 4.9t²

✦ Reorder the equation to form it into the quadratic formula.

✦ 4.9t² - 225t + 620 = 0

✦ Solve for t

✦ t = 43

It will take 43 seconds for the shell above the ground.

Hope that helps! ★ If you have further questions about this question or need more help, feel free to comment below or leave me a PM. -UnicornFudge aka Nadia

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