Question

5. A car at rest accelarates uniformly to
Speed of 40m/s in 20 sec calculate the
accelaration​

Answer 1

Answer:

Given:

Initial velocity = 0 m/s

Final velocity = 40 m/s

Time taken = 20 sec.

To find :

acceleration of the car.

Concept :

When velocity of a body changes with respect to time, there is involvement of force which actually accelerates the object.

Formulas used:

Let acceleration be denoted by "a"

then,

a =(Final Velocity - Initial velocity)/Time

Calculation:

a = (40 - 0)/20

=> a = 40/20

=> a = 2 m/s²

So the acceleration is 2m/s².

Answer 2

Question :-

A car at rest accelarates uniformly to

Speed of 40m/s in 20 sec calculate the

accelaration.

Answer :-

$\star \: \sf{\red{acceleration} \: = 2 \: \: \frac{m}{ {s}^{2} } }$

To Find :-

→ Acceleration

Formula used :-

$\rightarrow \small \: \sf{ \green{acceleration }\: = \frac{ \red{(final - initial) \: velocity}}{time} }$

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Explanation :-

Given that

• Final velocity = 40 m/s

• Initial velocity = 0 m/s

• acceleration (a) = ?

• time (t) = 20 seconds

Substitute these values in the given formula ,

$\rightarrow \sf{ a \: = \red{\frac{40 - 0}{20} }} \\ \: \\ \rightarrow \: \sf{ a = \green{ \frac{40}{20} }} \\ \\ \rightarrow \: \boxed{\sf{ a \: = \red{2}} \: \: \blue{ \frac{m}{ {s}^{2} } }}$

Therefore acceleration is 2 m/s^{2}

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Some important formula for you→

$\star \: \sf{ \green{ {v}^{2}} = \red{{u}^{2} + 2as}} \\ \\ \star \: \sf{\blue{velocity }= \frac{\red{displacement}}{time} } \\ \\ \star \: \sf{speed \: = \frac{\red{distance}}{time} } \\ \\ \star \: \sf{ \pink{kinetic \: energy }= \frac{1}{2} \: \green{m {v}^{2} }} \\ \\ \star \: \sf{ \blue{momentum} (p) =\red{ mv}}$

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