5) A car getting off a highway decelerates along the ramp at a rate of 2.5 meters per second'. If the car is on the ramp for 10 seconds and slows to a speed of 13 meters na second, what was its speed before it began decelerating?
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Step-by-step explanation:
Let us assume initial speed as 'u' and final speed as 'v' , acceleration as 'a' and time on the ramp as 't'
v = 13 m/s
a = -2.5 m/s^2 (negative because
decelerating)
t = 10 s
u = ?
v = u + at
or u = v - at
= {13 - (-2.5) x 10} m/s
= (13 + 25) m/s
= 38 m/s
Therefore, initial speed u = 38 m/s
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