Question

5. A car travelling at 22.4 m/s skids to a stop in 2.55
s. Determine the skidding distance of the car
(assume uniform acceleration).
​

Answer 1

ANSWER

Here, initial velocity, u=22.4m/s and final velocity, v=0 m/s

Time taken by car to stop t=2.55s

If a be the acceleration.

Using formula v=u+at,

0=22.4+a(2.55)

We get a=−8.78m/s

2

(negative signs means deceleration of car)

If d be the distance traveled by car.

Using formula v

2

−u

2

=2ad

0

2

−(22.4)

2

=2(−8.78)d

⟹ d=28.6m

Answer 2

Answer:

28.6

Explanation:

hope it helps u..........