5. A car was moving with a velocity of 10 m/s. Its momentum in Sl units was 10,000. On application of brakes, the car went to half its initial velocity in 2s. Find the braking force.
Answers
Answer:
10,000 = m × 10, m = 1000 kg
Using it again,
F = 1000 × (-5)/2 = -2500N
Explanation:
The braking force can be given as:
F = ma = m [(5-10)/2]
Now, to get mass, we can use the definition of momentum which we calculated as -2500N
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Answer:
Braking Torque (Tb) lives the moment of a braking force about the center of rotation. Tb = Fb .
Explanation:
Braking Torque (Tb) lives the moment of a braking force about the center of rotation. Tb = Fb . re Where re stands the practical disc radius. Calculated braking torques for the range of Twiflex brake calipers stand demonstrated in the brochure for a range of standard disc sizes.
The maximum vehicle braking force (Fb max) stands equivalent to the coefficient of road adhesion periods the weights normal to the roadway surface. Braking force exists the amount of energy that is required into your leg, from front to back, when your foot first hits the ground. A good way to imagine this is to imagine you exist running at full speed and controlling to stop suddenly. The maximum force you feel when you slam on the brakes exists as your peak braking force.
10,000 = m × 10, m = 1000 kg
Using it again,
F = 1000 × (-5)/2 = -2500N
The braking force can be given as:
F = ma = m [(5-10)/2]
Now, to get mass, we can use the definition of momentum which we calculated as -2500N
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