Question

5.
A charge 4uC is placed in an electric field of
magnitude 8 N/C. Find the force on it.
TA ne, 2210-6​

Answer 1

Answer:

E=F/q

rearrange the equation we get

F= E×q

F=8N×4×10^-6 N/C

F=32×10^-6N

hope it helps u