Question

5.
A charged particle having charge 3.2 x 10-1°C is
travelling with a speed of 1.0 x 106 ms-1. When it
passes perpendicular to the magnetic field 0.4 T,
then the force experienced by it is :
(1) 12.8 x 10-13 N (2) 1.28 x 10-13 N
(3) 19.2 x 10-15N (4) 1.92 x 10-15N​

Answer 1

Answer:

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Answer 2

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A charged particle having charge 3.2 ×10-19C travelling with the speed of 1.0× 106m/s . When it passes perpendicular to the magnetic field 0.4 T, then the force experienced by it is:-

(1) 12.8 x 10-13 N

(2) 1.28 x 10-13 N

(2) 1.28 x 10-13 N(3) 19.2 x 10-15N

(4) 1.92 x 10-15N

Let's first know about some symbols used in physics that are related to our question:-

V- V is used to represent velocity or a vector quantity.

Two different vetors are used to represent magnetic field.

Magnetic flux density or magnetic induction is symbolized by B.

Magnetic field stregth ir magnetic field intensity is symbolized by H.

q- q is used to represent charge on a particle. n for negative charge, p for postive charge and e for electronic charge.

Now let's solve your question:-

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Charge on particle= q =$\sf3.2 \times {10}^{ - 19}$

Speed= v= $\sf1 \times {10}^{6}$

Magnetic field= B=0.4T

Force= Bqv sinθ

θ= 90°, so sin 90=1

$\sf{F= 0.4×3.2×1× {10}^{( - 19 + 6)} }$

$\sf{F=1.28× {10}^{ - 13}N}$

So your answer is option (2).

Force experienced by the particle is $\sf1.28 \times {10}^{ - 13} N$

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