Math, asked by sakinapetiwala99, 4 months ago

5) A coin is biased such that a head is likely to occur four times more than that of a tail. Find the expected number
of heads when the coin is tossed twice (Correct upto 1 decimal point).​

Answers

Answered by Riddhimathakur1407
0

Answer:

2 by 4 it means 1 by 2 which is equal to 0.5

Answered by AneesKakar
0

Answer:

1.60

given,

A biased coin, in which the probability  is four times more than that of tails during a toss.

to find,

expected number of heads when the coin is tossed twice

solution,

to find the expected number of heads when the coin is tossed twice, we must calculate the probability of occurance of each, heads and tails first.

probability (Y) = Number of favorable outcomes of Y ÷ total number of possible outcomes

we know that the likelihood of heads is 4 times that of tails.

so,

the probability of occurance of heads = 4/5

the probability of occurance of tails = 1/5

Let the expected number of heads be X

now, if a coin is tossed twice,

X= probability of heads in one toss × total number of tosses

X= 4÷ 5 ×2

X= 1.6

Therefore, the expected number of heads when the coin is tossed twice is 1.60

#SPJ2

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