Math, asked by jeiyanmeena89, 5 months ago

5.
A company made 7,98,146 telephone calls out of which 86,197 were free. For
how many telephone calls the company was charged?
The difference of two numbers is 17,961. If the greater number is 4,12,629, find
6.
the smaller number.
7.
8.
Indian Railways has railway tracks of length 59,684 km. The National Highways
has roads of length 24,943 km. Find the difference.
3,43,392 people live in Goa and 3,51,462 live in Puducherry. Which town has
more people and by how much?
Find the difference between the greatest 5-digit number and the smallest
5-digit number.
0. Mother dairy produced 30,000 packets of milk in one day. It supplied 20,196
packets a day to various depots. How many packets were left behind?
9.​

Answers

Answered by manasranjan95189
2

\mathbb\blue{Answer}

1) 711949 calls they were charged.

2) 394668 is the smaller number.

3) 34741 is the difference between the length of the railway

track and the national highway

4) Puducherry has more people by 8070.

5) 89999 is the difference between greatest five digit number and the smallest five digit number.

6) 9804 packets were left behind

\mathbb\red{Solutuion}

1) Total number of calls =798146

free calls =86197

number calls for which the company was charged=798146-86197

=711949

2) the difference of the two numbers =17961

the greater number =412629

let the smaller number be x.

As per question,

412629-x = 17961

412629-17961=x

x=394668

3) length of Indian railway track=59684 km

length of the national highway=24943 km

difference of the railway track and national highway=59684-24943

=34741

4) people live in goa=343392

people live in Puducherry=351462

from above we conclude that puducherry has more people.

puducherry has more people by how much=351462-343392

=8070

5) the smallest five digit number=10000

the greatest five digit number=99999

difference of greatest five digit and smallest five digit no.=99999-10000

=89999

6) packets produced in one day=30000

packets supplied to depots =20196

packets left behind = 30000-20196

=9804 packets

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