Question

5. A constant current signal
across a parallel RLC circuits
gives an o/p of 1.4y at the
signal frequency of 3.89KHZ
and 4.1KHZ. At the frequency
of 4KHZ, the o/p voltage will be​

Answer 1

The Equator is the line of 0 degrees latitude. Each parallel measures one degree north or south of the Equator, with 90 degrees north of the Equator and 90 degrees south of the Equator. Aug 27, 2020-1 +2 +1 +1 +1 2] +3 -1 -1 -1 -2[04/10, 8:12 pm] SHAFNA: Therefore

Mn=(-7)+(+7)=○

The oxidation number of Mn in KMno4=+7

[04/10, 8:17 pm] SHAFNA: B] H2SO4

Oxidation number of H=+1

Oxidation number of O=-2

H--->(+1×2)+0--->(-8)=-6

Therefore

S=(-6)+(+6)=0

The oxidation number of S in H2SO4 =+6

[04/10, 8:27 pm] SHAFNA: 5) Redox reaction:-

a chemical reaction in which both oxidation and reduction processes take place simultaneously is known as redox reactions

*EXAMPLE*:- H2 + c12-->2Hcl

In the reaction hydrogen atom is Oxygen oxidized and chlorine atom is reduced these two reactions constitutes the complete chemical reaction

H2+Cl2 2-->2HCl

hair the process of oxidation and reduction take place simultaneously hence these two reactions are known as Redox rea ction

[04/10, 8:40 pm] SHAFNA: 6]A)MnO2

Oxidation number of O=-2

O--->(-2×2)

O--->(-4)

The oxidation number of O in MnO2=(-4)

Therefore

Mn=(-4)+(+4)=0

The oxidation number of Mn in MnO2=(+4)

B) Mn2O7

Oxidation number of O=-2

O-->(-2×7)

O-->(-14)

The oxidation number of O in Mn2O7=(-14)

Therefore

Mn2=(-14)+(+14)=0

Mn2=(+14)

The oxidation number of Mn in Mn2O7 = +14/2=+7

Explanation:

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