5. A cubical tank with side 5.5 m is painted on 4 walls and top.
a. How much is this surface in m??
b. If the paint costs * 23 per m², how much would it cost to paint the tank?
c. If labour cost is 1200, what is the total cost of painting the tank?
Answers
Answered by
1
Answer:
hope this will help you
Step-by-step explanation:
Area to be painted = area of the walls + area of ceiling
=2(hl+hb)+lb
=[2×(7×15+7×10)+(15×10)]=500 sq m
No. of cans required =
100
500
=5
Hence, 5 cans are required to paint the walls and the ceiling of the cuboidal hall.
Answered by
0
Step-by-step explanation:
5 is the answer please mark
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