Question

5. A cyclist travels a distance of 1 km in the first
hour, 0.5 km in the second hour and 0.3 km in
the third hour. Find the average speed of the
cyclist in (i) km h-1, (ii) m s-1.
Ans. (a) 0.6 km h-1, (b) 0.167 m s-​

Answer 1

Answer:

a) 0.6 kmh-1

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Step-by-step explanation:

1+0.5+0.3=1.8

1+1+1=3

1.8/3= 0.6

Answer 2

Answer:

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Step-by-step explanation:

d1=1km

t1=1hr

d2=0.5km

t2=1hr

d3=0.3km

t3=1hr

speed=distance/time

so

s1=d1/t1=1km/hr

s2=d2/t2=0.5km/hr

s3=d3/t3=0.3km/hr

average speed =s1+s2+s3 /t1+t2+t3

=1+0.5+0.3 / 1+1+1

=1.8/3

=0.6km/hr

0.6km/hr=0.6×1000/3600

=0.6×5/18

=0.1×5/3

=0.5/3

=0.16666666.......

≈0.167m/s