Question

5. A drop of radius 1mm is sprayed into 1000
droplets of same size. If surface tension of the
liquid is 40 dyne (cm-1), the amount of
workdone in the process is
1) 4.53erg
2) 4.53J
3) 4.53 x 10-43 4 ) 9.06 x 10-6J
Tilit into​

Answer 1

Thus the amount of work done in this process is  W = 4.53 x 10^-6 J

Option (2) is correct.

Explanation:

Given data:

• Radius of drop = 1 mm
• umber of droplets = 1000
• Surface tension = 40 dyne cm^-1

Solution:

W = 4 π R^2 T (n^1/3 - 1)  =

W = 4 x 3.14  (10^-3)^2 [ 1000^ 1/3 - 1 ] x 40 x  10^-3

W = 4 x 3.14 x 40 x 9 x 10^-9 J

W = 4521.6 x 10^-9 J

W = 4.53 x 10^-6 J

Thus the amount of work done in this process is  W = 4.53 x 10^-6 J