Question

5
A ekaryotic gene of 1000 base pairs containing several introns encodes a protein of 11 kDa. Assuming that
de average molecular weight of one amino acid is 110 Da, the total length (in base pairs) of all the introns
of the gene is
a 600
b. 720
C 697
d. 597​

Answer 1

Answer:

(B)

Explanation:

while the gene encodes protein they are reduce in no.