Question

5. (a) Express 64x³ +144x²y + 108xy² + 27y³ as a perfect cube and find its value when x = 6, y = 2.​

Answer 1

Answer:

answer for the given problem is given

Answer 2

$64{x}^{3}+ 144 {x}^{2} y + 108x {y}^{2} + 27 {y}^{3}$

$= (4x)^{3} + 3 \times (4x)^{2} \times 3y + 3 \times 4x \times (3y)^{2} + (3y)^{3}$

$= (4x + 3y)^{3}$

Now,

$x = 6$

$x = 2$

Therefore, the result will be,

$(4 \times 6 + 3 \times 2)^{3}$

$= (24 + 6)^{3}$

$= 30^{3}$

$= 27000$

$<marquee>Hope it helps you... please mark this answer as the brainliest and follow me... </marquee>$