Question

5. A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle?​

Answer 1

Step-by-step explanation:

If the number of animals increases, then it will take fewer days to last.

Then the two quantities are in inverse proportions.

Number of animals Number of days

20 6

(20 + 10) or 30 P

Let the required number of days be p.

x1y1 = x2y2

where x1 = 20, y1 = 6, x2 = 3

and y2 = p (let)

20 × 6 = 30 × p

p = 4

Hence the required number of days = 4.

Answer 2

Let the number of days be x

Total number of animals = 20 + 10 = 30

Here the number of animals and the number of days are in inverse proportion.

Therefore 20/30=x/6

x= 6 times 20/30=12 /3=4

Hence the food will last 4 days.

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