5. A fast train takes 3 hours less than a slow train for a journey of 600 km, if the speed of the slow train is 10 km/hr less than that of the fast train, the speeds of the two trains are
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SeldonAngmo:
hy @nikhil I got a different answer..
let's see whose answer will be correct
if she Mark's your answer as brainliest a swer, then yours is correct
or else my answer will be correct
u check mine I'll check urs.... correct me if I've got it wrong... I'll do d same
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hi @podilapu. distance = 600km
case1: time = t
speed = 600/t
case2: time = t+3
speed = 600/t+3
acc. to question, 600/t - 600/t+3 = 10
by cross multiplication, we'll get
t² + 3t - 180 = 0
t² + 15t - 12t - 180 = 0. ( by middle term splitting )
t ( 1 + 15 ) - 12 ( t + 15 )=0
t - 12 =0
t = 12----------(1)
then put this value in the equation of speeds of the two trains, we'll get
600/12=50
& 600/12+3= 40
hence the speed of d faster train = 50km/hr
n that of the slower train = 40km/hr.
seldon ≡^ˇ^≡
case1: time = t
speed = 600/t
case2: time = t+3
speed = 600/t+3
acc. to question, 600/t - 600/t+3 = 10
by cross multiplication, we'll get
t² + 3t - 180 = 0
t² + 15t - 12t - 180 = 0. ( by middle term splitting )
t ( 1 + 15 ) - 12 ( t + 15 )=0
t - 12 =0
t = 12----------(1)
then put this value in the equation of speeds of the two trains, we'll get
600/12=50
& 600/12+3= 40
hence the speed of d faster train = 50km/hr
n that of the slower train = 40km/hr.
seldon ≡^ˇ^≡
hello
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