Question

5.A father is 24 years older than his son, After 8 years he will be three times as old as his son find their present ages
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Answer 1

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Answer 2

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• Father os 24 years older than his son.

Let the ages of the son be x years.

So,

Father's age will be (x+24) years.

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• After 8 years father will be three times as old as his son.

After 8 years their ages will be,

Son = (x+8) years

Father = (x+24) + 8 = (x+32) years

ATQ,

⇒ $\boxed{\bf{3 (x+8) = (x+32)}}$

⇒ 3x + 24 = x + 32

[Transporting x to LHS and 24 to RHS]

⇒ 3x - x = 32 - 24

⇒ 2x = 8

[Transporting 2 to RHS]

⇒ x = 8 ÷ 2

$\red{\therefore}$ x = 4

Hence,

• The present age of the son is 4 years.
• And the present age of father is (x+24) = 4+24 = 28 years.