English, asked by samriddhi9555, 11 months ago

5. A flooring tile has a shape of parallelogram whose base is 18 cm and the correspondine
height is 6 cm. How many such tiles are required to cover a floor of area 540 m2
(If required you can split the tiles in whatever way you want to fill up the corners),​

Answers

Answered by Anonymous
1

No. Of tiles = Area of floor/ area

                                      of //GM.

NOW, AREA OF // GM=

                             BASE×HEIGHT

      = (18× 6)cm²

  = 108cm²

Therefore,  no.  of  tiles = 540m2/

                                           108cm²

                           =    540×100cm²/

                                          108cm²

                       = (54000/ 108)cm²

                      = 500

This is the best answer.

Mark this answer brainliest.

Answered by Anonymous
7

Base of the parallelogram-shaped flooring tile = 18 cm and its height = 6 cm

So,

Area of one tile = Base × Height

= 18 × 6

= 108 cm2

We have the area of floor = 540 m2

Hence, number of tiles = Total area/ Area of one tile

= (540 x 100 x 100)/108 [As, 1 m2 = (100 x 100) cm2]

= 50000

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