Question

.5. A flooring tile has a shape of parallelogram whose base is 18 cm and the correspondine
height is 6 cm. How many such tiles are required to cover a floor of area 540 m2
(If required you can split the tiles in whatever way you want to fill up the corners),​​

Answer 1

Answer:

48,148$\frac{4}{27}$ tiles

Step-by-step explanation:

Total area of the room = 520 $m^{2}$

No of tiles required = $\frac{Total. area. of. the. room}{Area. of. a. tile}$

Area of a parallelogram tile = base × height

=> 18×6 cm$^{2}$

=> 108 cm$^{2}$

=> 520 m^2 = 5200000 cm^2

=> $\frac{5200000}{108}$

=> 48,148$\frac{4}{27}$ tiles

Answer 2

Base of the parallelogram-shaped flooring tile = 18 cm and its height = 6 cm

So,

Area of one tile = Base × Height

= 18 × 6

= 108 cm2

We have the area of floor = 540 m2

Hence, number of tiles = Total area/ Area of one tile

= (540 x 100 x 100)/108 [As, 1 m2 = (100 x 100) cm2]

= 50000