Math, asked by sarjeet25979, 18 days ago

5. A flooring tile has a shape of parallelogram whose base is 18 cm and the corresponding height is 6 cm. How many such tiles are required to cover a floor of area 540 m?? (If required you can split the tiles in whatever way you want to fill up the corners). ​

Answers

Answered by choprasiddharth10
8

Answer:

50000 tiles

Step-by-step explanation:

this can be solved as

area of a llgm = b ×h

on converting values to metre

area=.18×.06=0.0108m²

no .of tiles required=

540÷.0108=50000 tiles ans.

hope it helps!

Answered by oODivineGirlOo
3

Answer:

Given,

Base of the parallelogram - shaped flooring tile =18cm and its height =6cm

So,

Area of one tile =Base×height=18×6=108cm2

We have the area of floor =540m2

Hence, number of tiles = Total area / Area of one tile

=108(540×100×100) [∵1m2=(100×100)cm2]

=50000

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