Question

5. A force of 100 N acts 0.5 sec. on a body of mass 20 kg which is initially at rest. The
velocity attained by the body is
(A) 5 m/sec
(B) 2.5 m/sec (C) 20 m/sec
(D) None of these​

Answer 1

Answer:

a=100/20=5

v=u+at :,v=5*5=25

Answer 2

Explanation:

$f = ma \\ 100 = 20 \times a \\ a = 5m \: per \: s {}^{2} \\ as \: we \: know \: \\ v = u + at \\ by \: putting \: the \: given \: value \\ v = 0 + 5 \times 0.5 \\ v = 2.5m \: per \: sec$