Question

5 A force of 20 newton is applied
on the area of a Cross Section
of a cylinder 5 x 10 of - 4 m². Then
find the pressure produced in
the cylinder​

Answer 1

Answer:

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Step-by-step explanation:

In a hydraulic press a force F1 applied to the smaller plunger creats a pressure F1A1 in the liquid and this pessure is transmitted equally throughout the liquid and acts on the larger plunger. The thrust acting on te larger plunger upwards due to tis pressure is

F2=A2(F1A1)

Hence, the thrust on A2 is magnified by A2A1 times

a.F1A1=205×10−4=40000N/m2

b. F2=F1×(A2A1)=20×10−25×10−4=400N

work done by force F1=F1d1=20×0.1=2J

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Answer 2

Answer:

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