5. A force of 500 N acts on the surface of area 0.3 cm normally. What would be the
thrust and pressure on the surface?
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Answer:
pressure = F/A (force per unit area)
F= 500n
A= 0.3cm2 = 0.3/100×100 = 0.03
p=FA
• 1200×0.03
• 36 n/m2 = pa (pa means Pascals)
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