Question

5. A force produces an acceleration of 16 ms-2 in a
body of mass 0.5 kg, and an acceleration of 4-0 m/s2
in another body. If both the bodies are fastened
together, then how much acceleration will be
produced by this force ? [Ans. 3-2 ms-21
000 5 Iro falls from the ton of a cliff​

Answer 1

Answer:

a1= 16 m/s²

m1 = 0.5 kg

force = F = m1a1 = 16 x 0.5 = 8N

same force is applied to the second mass; m2

F = m2a2 = 8N

or  

m2 = 8/a2

m2 = 8/4 = 2kg

total mass = m1 + m2 = 0.5 + 2 = 2.5 kg

force is same as before

so,

a = F/M

= 8/ 2.5

= 3.2 m/s²

Explanation:

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Answer 2

GivEn:

• Acceleration produced by a body = 16 m/s²

• Mass of a body, m = 0.5 kg

• Acceleration produced by another body = 4 m/s²

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To find:

• If both the bodies are fastened together, then how much acceleration will be produced by this force ?

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SoluTion:

Let mass of one body be $\sf m_1$ and mass of another body be $\sf m_2$.

Let Acceleration produced by first body be $\sf a_1$ and by another body be $\sf a_2$.

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$\bf We\;have \begin{cases} & \text{Acceleration, \sf a_1 = 16 m/s^2 } \\ & \text{Mass, \sf m_1 = 0.5 kg } \end{cases}$

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We know that,

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$\star\;{\boxed{\bf{\purple{F = ma}}}}$

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$\;\;\;\;\;\;\small\sf \underline{Putting\;values\;:}$

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$:\implies\sf F = 0.5 \times 16$

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$:\implies\bf F = 8\;N$

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☯ Acceleration of another body = 4 m/s²

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So,

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$\bf Here \begin{cases} & \text{Acceleration, \sf a_2 = 4 m/s^2 } \\ & \text{Force, F = 8 N} \end{cases}$

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$\;\;\;\;\;\;\small\sf \underline{Putting\;values\;:}$

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$:\implies\sf 8 = m_2 \times 4$

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$:\implies\sf m_2 = \cancel{ \dfrac{8}{4}}$

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$:\implies\bf m_2 = 2\;kg$

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☯ When both bodies are fastened,

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$:\implies\sf M = m_1 + m_2$

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$:\implies\sf M = 0.5 + 2$

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$:\implies\bf M = 2.5\;kg$

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${\underline{\sf{\bigstar\;Now,\;we\;have\;to\;find\; acceleration\;:}}}$

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$:\implies\sf F = Ma_2$

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$:\implies\sf a_2 = \dfrac{8}{2.5}$

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$:\implies{\underline{\boxed{\bf{\pink{a_2 = 3.2\;m/s^2}}}}}\;\bigstar$

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$\therefore$ If both the bodies are fastened together, then acceleration produced by this force is 3.2m/s².