Question

5. A given length of a wire is doubled on itself and this process is repeated once again. By what factor does the resistance of the wire change? ​

Answer 1

let the length of wire =L

cross section area =a

new length =L/4

new cross section area =4a

as resistance = resistivity ×L/a=R

new resistance = resistivity × (L/4)/4a= R/16

new resistance is (1/16) times old resistance