Question

5. A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of
tin-plating it on the inside at the rate of 16 per 100 cm​

Answer 1

Answer:

Rs. 27.72 ,I think

Step-by-step explanation:

d =2r so, r =

$\frac{10.5}{2} = 5.25cm$

now , c.s.a. of hemisphere =

$2\pi {r}^{2}$

=

$2( \frac{22}{7} )(5.25)(5.25) = \frac{1212.75}{7} = 173.25 \: {cm}^{2}$

so ,area of bowl is 173.25 cm^2

now ,rate of its painting =

$\frac{173.25}{100} \times 16 = rs. \: 27.72$

hope helps.

Happy New year