5. A hemispherical depression is cut out from one face of a cubical wooden block such
that the diameter 1 of the hemisphere is equal to the edge of the cube. Determine the
surface area of the remaining solid.
PLEASE someone help me I will make them brainlist❤️
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Answer:
It is given that a hemisphere of radius 1/2 is cut out from the top face of the cuboidal wooden block.
Therefore, surface area of the remaining solid
= surface area of the cuboidal box whose each edge is of length l − Area of the top of the hemispherical part + curved surface area of the hemispherical part
=6l^2−πr^2+2πr^2
=6l ^2−π( 1/2)^2+2π( 1/2)^2
=6l^2−4πl^2/4+ 2πl^2/2
(24+π) sq.units
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