5. A hydroelectric power station takes its water from a
lake whose water level is at a height of 50 m above
the turbine. Assuming an overall efficiency of 40%,
calculate the mass of water which must flow through
the turbine each second to produce power output of
1 MW. (Take g = 10 m s-2).
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Answer:
500kg/s
Explanation:
Here we have to calculate mass flow rate of water through turbine.
Efficiency = power output/ power input
40/100 = 1 MW / power input
power input = 100/40 MW
Power input = 2.5 MW
now power input = mass flow rate * g * H
2.5 MW = m * 10 * 50
2.5 * 1000000/500 = 2.5 *200
= 500 kg/s
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