Question

5. A hydroelectric power station takes its water from a
lake whose water level is at a height of 50 m above
the turbine. Assuming an overall efficiency of 40%,
calculate the mass of water which must flow through
the turbine each second to produce power output of
1 MW. (Take g = 10 m s-2).
Ans. 5000 kg​

Answer 1

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Potential energy = mgh

Efficiency = 40%

Useful work done = 40% of potential energy

= 40/100 (mgh) = 0.4 × (m × 10 × 50)

= 200m

Power = Work done per. second

1MW = 200 × mass of water flowing each second

1 × 10 power =6w = 200 × mass of water flowing each second

Mass of water flowing each second = 1 × 10 power 6

200

= 5000

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