Question

5. (a) In AABC, AB = 17cm, BC = 15cm, CA = 8cm and LACB = 90°
Name the triangle in two different ways and also define the type of
triangle.​

Answer 1

Step-by-step explanation:

According to the question,

AB = 8 cm, BC = 15 cm, AC = 17 cm

AB = Adjacent Side, BC = Opposite Side, AC = Hypotenuse.

Now we need to find Sin A, Cos A, and Tan A.

Let us calculate Sin A first,

Sin A = Opposite / Hypotenuse

=> Sin A = BC / AC

=> Sin A = 15 / 17

Cos A = Adjacent / Hypotenuse

=> Cos A = AB / AC

=> Cos A = 8 / 17

Tan A = Opposite / Adjacent

=> Tan A = BC / AB

=> Tan A = 15 / 8