Question

5 अंकों की वह छोटी से छोटी संख्या ज्ञात कीजिये जिसे 40, 60 तथा 75 से भाग करने पर क्रमशः 31,51 तथा 66 शेषफल बचता है?​

Answer 1

Answer:

9

Step-by-step explanation:

this is the right answer.

Answer 2

The required number is 10191.

Step-by-step explanation:

We need to find the smallest 5 digit number which given 31,51 and 66 remainder wen it divided by 40, 60 and 75 respectively.

LCM of 40, 60 and 75 = 600

Smallest 5 digit number = 10000

$600\times 16=9600$

$600\times 17=10200$

10200 is the smallest 5 digit number which is divisible by 600.

Difference of dividend and remainder = 40-31=9

Difference of dividend and remainder = 60-51=9

Difference of dividend and remainder = 75-66=9

Now subtract the difference of dividend and remainder from 10200.

$10200-9=10191$

Therefore, the required number is 10191.

#Learn more

The smallest number which when divided by 30, 45, 75 and 60 leaves a remainder of 21, 36, 66 and 51 respectively is.

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