Question

5.
A man goes 10 m due east and then 24 m due north. Find his distance from the starting point.​

Answer 1

Answer:

24 metres.

Step-by-step explanation:

Let the initial position of the man be O and his final position be B.

Since the man goes 10 m due east and then 24 m due north.

Therefore, ∆AOB is a right triangle right-angled at A such that OA

= 10 m and AB

= 24 m.

Answer 2

26m

Step-by-step explanation:

We have

Towards North=24m

Towards East=10m

Using Pythagoras Theorem

(Hypotenuse)

2

=(base)

2

+(height)

2

=(10)2 +(24)2

=100+576

=676

=(26)2

Starting point =

$\sqrt{hypotenuse}2$

=

$\sqrt{26}$

= 26 m