Question

5. A man is 3 times as old as his son. After 15 years, he will be only twice as old as his son. find their present age
present ages.
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Answer 1

Answer:

let man's age be x years and his sons age be t years

A.T.P.

x=3y

after 15 years=> x+15=2 (y+15)

x+15=2y+30

put x=3y in above

3y+15=2y+30

3y-2y=30-15

•°• y=15

put y in x=3y

x=3 (15)

x=45

man's age=45 years

son's age=15 years

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Answer 2

Answer:

Present age of son = 15 years

Present age of father = 45 years

Step-by-step explanation:

Let,

Present age of son = x

Present age of father = 3x

After 15 years,

The age of son = x + 15

The age of father = 3x + 15

➨ 3x + 15 = 2(x + 15)

➨ 3x + 15 = 2x + 30

➨ 3x - 2x = 30 - 15

➨ 1x = 15

➨ x = 15 years

Present age of son = 15 years

Present age of father = 3x

➨ 3 (15)

➨ 3 × 15

➨ 45

Present age of father = 45 years