Physics, asked by kalasangam2000, 11 months ago

5. A man raises a box of mass 50 kg to a height
of 2 m in 20 s, while another man raises the same
box to the same height in 50 s.
(a) Compare : (i) the work done, and (ii) the power
developed by them.
(b) Calculate : (i) the work done, and (ii) the power
developed by each man. Take g = 10 N kg!.
Ans. (a) (i) 1:1 (ii) 5 : 2,
(b) (i) 1000 J, 1000 J (ii) 50 W, 20 W
no limun water bucket​

Answers

Answered by amankumar44878
2

Answer:

Work done in raising a 50kg mass to a height 2m against the force of gravity is: W = mg × h = mgh Hence both men will do the same amount of work. Hence, work done by A/work done by B = mgh/mgh = 50 x 10 x 2/50 x 10 x 2 = 1/1 = 1: 1 (ii) First man A takes 2 minutes to raise 50 kg mass Second man B takes 5 minutes to raise 50 kg mass. Power developed by man A = work done/Time taken mgh/t = 50 x 10 x 2J/120S = 25/3W Power developed by man B = work done/Time taken = mgh/t = 50 x 10 x 2J/5 x 60s = 10/3 W Power developed α 1/time taken Power developed by A/Power developed by B = (25/3)/(10/3) = 25/10 = 5/2 = 5 : 2Read more on Sarthaks.com - https://www.sarthaks.com/143428/a-man-raises-a-box-of-mass-50-kg-to-a-height-of-2-m-in-2-minutes-while-another-man-raises-the-same

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