Physics, asked by fulchand1646, 11 months ago

5)a motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is:

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Answered by rishu6845
0

Answer:

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Answered by VelvetBlush
8

Let the speed of the stream be x km/h

\therefore Speed Downstream = (15+x) km/h

Speed upstream = (15-x)km/h

Time taken to travel 30 km downstream = \sf{\frac{30}{15+x}h}

Time taken to travel 30 km upstream = \sf{\frac{30}{15-x}h}

Given, total time taken =

\sf\green{4 \: hours \: 30 \: mins. = (4 +  \frac{1}{2} )h =  \frac{9}{2} h}

\longrightarrow\sf\red{ \frac{30}{15 + x}  +  \frac{30}{15 - x}  =  \frac{9}{2}}

\longrightarrow \sf\red{\frac{10}{15 + x}  +  \frac{10}{15 - x}  =  \frac{3}{2} }

\longrightarrow \sf\red{\frac{10(15 - x + 15  + x)}{(15 + x)(15 - x)}  =  \frac{3}{2} }

\longrightarrow\sf\red{10 \times 30 \times 2 = 3(225 -  {x}^{2} )}

\longrightarrow\sf\red{200 = 225 \times  {x}^{2}}

\longrightarrow \sf\red{{x}^{2}  = 25 \: or \: x =  ±5}

As speed cannot be negative, x ≠-5, so x = 5

Hence, the speed of the stream = 5km/h

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