5. A number consists of three digits, the right hand being zero. If the left hand and the middle digits be
interchanged the number is diminished by 180. If the left-hand digit be halved and the middle and
right-hand digits be interchanged the number is diminished by 454. Find the number.
[Hint. Let the original number be 100a+10b+0, i.e., 100a+10b, then, by the first condition
(100a+10b)-(100b + 10a) = 180 = a-b= 2
By the second condition, new number = 100 +0+ b = 50a + b
2
and so (100a+10b) - (50a + b) = 454 = 50a +9b = 454].
a
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Answer:
The number will be 860.
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