5. A number is divided into two parts, such that one part is 10 more than the other. two parts are in the ratio 5 : 3, find the number and the If the two parts.
Answers
Given :
- A number is divided into two parts, such that one part is 10 more than the other.
- Two parts are in the ratio 5 : 3.
To find :
- The number and the If the two parts =?
Step-by-step explanation :
It is Given that :
The two parts are in the ratio 5:3.
So,
Let, the first number be 5x.
Then, the second number be 3x.
As given second number is 10 more than the other, so it will be 3x+10.
According to the question :
→ 5x = 3x+10
→ 2x = 10
→ x = 5
Therefore, We got the value of, x = 5.
Hence,
The first number becomes, 5x = 5(5) = 25
The second number becomes, 3x = 3(5) =15.
So, The new number will be 25+15 = 40.
Answer:
- Ratio of Numbers = 5 : 3
- One Part is 10 more than Other.
✩ One Part⠀⠀⠀⠀ ⠀:⠀⠀⠀⠀ ⠀ Other Part
⠀⠀⠀⠀5⠀⠀⠀⠀⠀ ⠀ ⠀ :⠀⠀⠀⠀⠀ ⠀ ⠀3
Difference between Ratio is (5 - 3) = 2
We will Divide The Real Difference of Parts i.e. 10 by 2, After that We will Multiplying this by Each of Ratio.
⇴ Difference /Diff. of Ratio
⇴ 10 /2
⇴ 5 ⠀⠀[ Number to Multiply Ratios ]
⠀⠀⠀⠀ ⠀ ⠀─────────────
• One Part = 5 × 5 = 25
• Other Part = 3 × 5 = 15
━━━━━━━━━━━━━━━━━━━━
☢ The Required Number :
⇏ Number = One Part + Other Part
⇏ Number = 25 + 15
⇏ Number = 40
∴ Required Number is 40 and two different parts are 25 and 15 respectively.