Question

5. A number is divided into two parts, such that one part is 10 more than the other. two parts are in the ratio 5 : 3, find the number and the If the two parts.​

Answer 1

Given :

• A number is divided into two parts, such that one part is 10 more than the other.

• Two parts are in the ratio 5 : 3.

To find :

• The number and the If the two parts =?

Step-by-step explanation :

It is Given that :

The two parts are in the ratio 5:3.

So,

Let, the first number be 5x.

Then, the second number be 3x.

As given second number is 10 more than the other, so it will be 3x+10.

According to the question :

→ 5x = 3x+10

→ 2x = 10

→ x = 5

Therefore, We got the value of, x = 5.

Hence,

The first number becomes, 5x = 5(5) = 25

The second number becomes, 3x = 3(5) =15.

So, The new number will be 25+15 = 40.

Answer 2

Answer:

• Ratio of Numbers = 5 : 3
• One Part is 10 more than Other.

✩ One Part⠀⠀⠀⠀ ⠀:⠀⠀⠀⠀ ⠀ Other Part

⠀⠀⠀⠀5⠀⠀⠀⠀⠀ ⠀ ⠀ :⠀⠀⠀⠀⠀ ⠀ ⠀3

Difference between Ratio is (5 - 3) = 2

We will Divide The Real Difference of Parts i.e. 10 by 2, After that We will Multiplying this by Each of Ratio.

⇴ Difference /Diff. of Ratio

⇴ 10 /2

⇴ 5 ⠀⠀[ Number to Multiply Ratios ]

⠀⠀⠀⠀ ⠀ ⠀─────────────

• One Part = 5 × 5 = 25

• Other Part = 3 × 5 = 15

━━━━━━━━━━━━━━━━━━━━

☢ The Required Number :

⇏ Number = One Part + Other Part

⇏ Number = 25 + 15

⇏ Number = 40

∴ Required Number is 40 and two different parts are 25 and 15 respectively.